Question

O solutie de concentratie c are masa m.Calculati cantitatea de apa care trebuie adaugata pt a scadea concentratia de n ori

Answer 1

c=concentratia
m=masa
m apa2=?
c-c/n
c=md/ms*100
ms=md+m apa1
c/n=(md/md+m apa)*100
m apa=m apa1+m apa2
c=md/(md+m apa)*100*n
md/(md+m apa1)*100=md/(md+m apa)*100*n
1/md+m apa1=n/md+m apa
md+m apa1=md+m apa/n
md*n+m apa1*n=md+m apa1 +m apa2
m apa 2=(md+m apa1)*(n-1)