Question

o sosea de 27 de Km este reparata in 3 zile. In prima zi se repara 5supra9 din sosea,iar a doua zi 2supra3 din rest.Cati Km de sosea au mai ramas de reparat pt a treia zi?

Answer 1

[tex]I(prima~zi)= \frac{5}{9} *x\ \textless \ =\ \textgreater \ \frac{5}{9} *27km=15km=\ \textgreater \ prima ~zi=15 km [/tex]
$~Aflam~restul~din~a~doua~zi: \frac{2}{3} (27km-15km)\ \textless \ =\ \textgreater \ \frac{2}{3} *12km=8km$
Aflam a treia zi
I zi+IIzi+IIIzi=27km
$15km+8km+III ~zi=27km\ \textless \ =\ \textgreater \ 23km+ III ~zi=27km\ \textless \ =\ \textgreater$
$III~zi=27km-23km=4km=\ \textgreater \ III~zi=4km$