Question

O substanta organica A cu masa molara M=122 da la analiza urmat rezultate:din 0,2440 g substanță se obtin 0,616 CO2 si 0,1080g H2O.Sa se stabileasca formula procentuala,bruta,si moleculara a substantei A.

Answer 1

din 0,2440g....se obtin....0,616gCO2........0,1080gH2O
      122g(1mol).................X..........................Y
x= 308gCO2--------> niu= m/miu;    niu= 308g/44g/mol= 7molCO2=7molC
Y= 54gH2O------->                           niu=54g/18g/mol=3molH20--> 6molH
FORMULA MOLECULARA : C7H6Oz
122g/mol= 7x12gC+6x1gH+16z gO------> z=2
FORMULA MOLECULARA : C7H6O2

FORMULA PROCENTUALA
122g compus........84gC.........6gH........32gO
100g.........................X..............Y...........Z...............................caluleaza !!!!

FORMULA BRUTA   (C3,5 H3 O)2