Question

O substanta organica are raportul de masa C:H:O = 6:1:8. Daca are masa moleculara 180 g/mol, calculati formula moleculara.

Answer 1

C=6/12=0,5 moli C   ||:0,5 ⇒ 1 atom C

H=1/1= 1 mol H  ||:0,5 ⇒ 2 atomi H

O=8/16= 0,5 moli O ||:0,5 ⇒ 1 atom O

F.B ⇒ (CH₂O)n

F.M ⇒ 12n+2n+16n=180 ⇒ 30n=180 ⇒ n=6

⇒ C₆H₁₂O₆ - glucoza