Question

o substanță organica cu masa molara 86 are concentratia de C=69,76%,H=11,62%si O=18,62%. Sa se afle formula moleculara a substantei ​

Answer 1

verificam daca procentele = 100%

=> 69,76 + 11,62 + 18,62 = 100%, verifica

notam compusul CaHbOc

avem 12a g C + b g H + 16c g O

100% compus .......... 69,76% C ........... 11,62% H ........... 18,62% O

86 g compus .......... 12a g C .............. b g H ................... 16c g O

=> a = 5, b = 10, c = 1

=> Fm. = C5H10O1