Question

observa ca numitorii urmatoarelor perechi de fractii au cel mai mare divizor comun egal cu 1 aducetil la cel mai mic numitor comun si apoi stabiliti care dintre ele este mai mare:1/2;si 7/15;3/4si16/25;3/14si2/9 ;7/12si8/5.cum se rezolva

Answer 1

a) 1/2 si 7/15 →cmmmc al nr (2,15)=2×15=30 →amplifica prima fractie cu 15, iar a doua fractie cu 2 (1×15)/(2×15)=15/30 (7×2)/(15×2)=14/30; 15/30> 14/30

1/2↓ > ↓7/15 b) 3/4 si 16/25 ; (4,25)=4×25=100 ; (3×25)/(4/25)=75/100 ; (16×4)/(25×4)=64/100 ; 75/100> 64/100 3/4 16/25 c) 3/14 si 2/9 ; (14,9)=14×9=126 ; (3×9)/(14×9)=27/126 <(2×14)/(9×14)=28/126; 27/127 <28/129 3/14 2/9 d) 7/12 si 8/5 ; (16,5)=12×5=60; (7×5)/(12×5)=35/60 <(8×12)/(5×12)=96/60; 35/60 <96/60 7/12 <8/5