Question

obțineți fracții ireductibile prin simplificarea fracțiilor
7supra 14, 11 supra 33, 23 supra 46, 180 supra 360, 1400 supra 2800, 220 supra 22, 13 supra 1313, 401 supra 1203, 824 supra 206 VA ROGGGGG​

Answer 1

Răspuns:

$\frac{7}{14}=\frac{1}{2} \\\\\frac{11}{33} = \frac{1}{3} \\\\\frac{23}{46} = \frac{1}{2} \\\\\frac{180}{360} = \frac{1}{2} \\\\\frac{1400}{2800} = \frac{1}{2} \\\\\frac{220}{22} =\frac{10}{1} \\\\\frac{13}{1313} = \frac{1}{101} \\\\\frac{401}{1203} =\frac{1}{3} \\\\\frac{824}{206} = \frac{4}{1}$

coroană?