Question

OFER COROANA! Aflati integrala functiei F(x)=3x la puterea a 2 + x + 1 daca f(1)=17

Answer 1

$F(x)= \int\limits {(3x^2+x+1)} \, dx = \frac{3x^3}{3}+ \frac{x^2}{2}+x+C$, aflam constanta din conditia data F(1)=17, 1+1/2+1+C=17 ⇒C=14,5 deci avem F(x)=x³+x²/2+x+14,5.