Question

OFER COROANA PENTRU REZOLVAREA COMPLETA !!

Answer 1

Legate in serie:

E_s=3•E

r_s=3•r

$I_1=\frac{E_s}{R+r_s}$

Legate in paralel:

E_p=E

r_p=r/3

$I_2=\frac{E_p}{R+r_p}$

Dar I1=I2 =>

$\frac{E_s}{R+r_s}=\frac{E_p}{R+r_p}$

$\frac{3E}{R+3r}=\frac{E}{R+\frac{r}{3}}$

$\frac{3}{R+3r}=\frac{1}{R+\frac{r}{3}}$

$R+3r=3(R+\frac{r}{3})$

$R+3r=3R+r$

$2r=2R$

Deci R=r