Question

OFER CORONITA
De impartit direct porportional nr 1500 cu nr 2,3,5

Answer 1

a,b,c ∈ N
[tex] \frac{a}{2}= \frac{b}{3}= \frac{c}{5}= \frac{a+b+c}{2+3+5}= \frac{1500}{10}=150 [/tex] 
$\frac{a}{2}\ \textless \ =\ \textgreater \ 150=300$
$\frac{b}{3}\ \textless \ =\ \textgreater \ 150=450$
$\frac{c}{5}=150\ \textless \ =\ \textgreater \ 750$