Question

Olimpiada de matematica. Clasa V-a.
Nu reusesc sa rezolv.
Multumesc pentru ajutor.

Answer 1

a=1+7^49:7^48-(49+14):9=1+7-63:9=8-7=1
b=12345-123×4×25-8×9×5:8=12345-492×25-72×5:8=12345-12300-360:8=45-45=0
a^b=1^0=1
b^a=0^1=0

Answer 2

$a=1+7^{49}:(7\cdot 7^2 \cdot 7^{45})-(7^2+7\cdot 2):3^2=\\ =1+7^{49}:7^{1+2+45}-(49+14):9=\\ =1+7^{49}:7^{48}-63:9=1+7^{49-48}-63:9=1+7-7=1\\ \boxed{a=1}\\\\ b=12345-123\cdot 2^2 \cdot 5^2-2^3\cdot3^2\cdot5:8 =\\ =12345-123\cdot 4 \cdot 25-8\cdot9\cdot5:8 =\\ =12345-123\cdot 100-9\cdot5 =12345-12300-45 = 45-45=0\\ \boxed{b=0}\\\\ a^b = 1^0 = \boxed{1}\\ b^a = 0^1 = \boxed{0}$