Question

ordonați crescător 5 la puterea 15;3 la puterea 35; 12 la puterea 10

Answer 1

${5}^{15} = {5}^{3 \times 5} = ( {5}^{3} )^{5} = {125}^{5}$

${3}^{35} = {3}^{7 \times 5} = ({3}^{7} )^{5} = {2187}^{5}$

${12}^{10} = {12}^{2 \times 5} = ( {12}^{2} )^{5} = {144}^{5}$

$= > {125}^{5} < {144}^{5} < {2187}^{5} = > \\ = > {5}^{15} < {12}^{10} < {3}^{35}$