Question

Ordonați crescător numerele
a=1,2(3)+2,3(4)+3,4(5)+4,5(6)
b=1,(23)+2,(34)+3,(45)+4,(56)
Dau coroană

Answer 1

a=1,2(3)+2,3(4)+3,4(5)+4,5(6)
a = (123-12)/90+(234-23)/90+(345-34)/90+(456-45)/90

a = 111/90+211/90+311/90+411/90

a = (111+211+311+411)/90

a = 1 044/90

a = 11,6

b=1,(23)+2,(34)+3,(45)+4,(56)

b=(123-1)/99+(234-2)/99+(345-3)/99+(456-4)/99
b=122/99+232/99+342/99+452/99

b = (122+232+342+452)/99

b = 1 148/99

b = 11,(59)

a > b

crescator:
b ; a .
11,(59) ; 11,6