Question

Ordonati urmatorii compusi chimici in ordine crescatoare a procentului de aluminiu din molecula:
Al(OH)3, AlCl3, Al2(SO4)3, Al2O3.

Answer 1

Răspuns:

MAl(OH)3=27+3x16+3x1=78g/mol

78g Al(OH)3....................27gAl

100g Al(OH)3....................x%Al

x=27x100/78=34,61%Al

MAlCl3=27+3x35,5=133,5g/mol

133,5gAlCl3....................27gAl

100g AlCl3....................y%Al

y=27x100/133,5=20,22%Al

MAl2(SO4)3=2x27+3x32+12x16=342g/mol

342gAl2(SO4)3....................27gAl

100g Al2(SO4)3....................z%Al

z=100x27/342=7,89%Al

MAl2O3=2x27+3x16=102g/mol

102g Al2O3....................27gAl

100gAl2O3....................t%Al

t=27x100/102=26,47%Al

Al2(SO4)3, AlCl3, Al2O3, Al(OH)3

Explicație: