Question

ordoneaza puterile: 5 la 60, 3 la 100, 7 la 80

Answer 1

$5^{60}=(5^{3})^{20}=125^{20}$

$3^{100}=(3^{5})^{20}=243^{20}$

$7^{80}=(7^{4})^{20}=2401^{20}$

$125^{20}<243^{20}<2401^{20}$

$=> 5^{60}<3^{100}<7^{80}$