Question

Oricine, va rog frumos sa ma ajutati cu problema 4 de mai jos, dau inima, coroana si 5 stele
va multumesc!!!

Answer 1

Răspuns:

Explicație pas cu pas:

Raspunsul il ai in paginile de mai jos. Paginile sunt numerotate. Sper sa intelegi.

Answer 2

 

$\displaystyle\bf\\a)\\Casuta~1~Rrandul~1=\frac{6}{\sqrt{3}}=\frac{6\sqrt{3}}{3}=2\sqrt{3} \\Casuta~3~Rrandul~1=\sqrt{108}=\sqrt{36\times3}=6\sqrt{3}\\Casuta~3~Rrandul~3=4\sqrt{12}=4\sqrt{4\times3}=4\times2\sqrt{3}=8\sqrt{3}\\Diagonala~1=2\sqrt{3}+5\sqrt{3}+8\sqrt{3}=15\sqrt{3}\\Completam:\\ \boxed{\Big2\sqrt{3}}\boxed{\Big7\sqrt{3}}\boxed{\Big6\sqrt{3}}\\ \boxed{\Big9\sqrt{3}}\boxed{\Big5\sqrt{3}}\boxed{\Big1\sqrt{3}}\\ \boxed{\Big4\sqrt{3}}\boxed{\Big3\sqrt{3}}\boxed{\Big8\sqrt{3}}$

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$\displaystyle\bf\\b)\\Casuta = C~si~Randul=R\\C3R1=7\sqrt{8}=7\times2\sqrt{2}=14\sqrt{2}\\C1R2=\sqrt{242}=11\sqrt{2}\\C1R3=\frac{24}{\sqrt{2}}=\frac{24\sqrt{2}}{2}=12\sqrt{2}\\ Diagonala~2=12\sqrt{2}+13\sqrt{2}+14\sqrt{2}=39\sqrt{2}\\Completam:\\\\\boxed{\Big16\sqrt{2}}\boxed{\Big~\,9\sqrt{2}}\boxed{\Big14\sqrt{2}}\\ \boxed{\Big11\sqrt{2}}\boxed{\Big13\sqrt{2}}\boxed{\Big15\sqrt{2}}\\ \boxed{\Big12\sqrt{2}}\boxed{\Big17\sqrt{2}}\boxed{\Big10\sqrt{2}}$