Question

Ovidiu,Marian si Alexandra au impreuna 100nuci.Daca fiecare mananca acelasi nr de nuci lui Ovidiu ii raman 39 nuci,lui Marian ii raman 25 nuci ,iar Alexandrei ii raman 21 nuci .Cate nuci a avut fiecare?
Prin reprezentare grafica

Answer 1

Ovidiu ------39 Marian------25 Alexandra----21. Total 100 Egalam partile 100-39-25-21=15 Aflam un segment 15:3=5. Un segment=5 Cate nuci are ovidiu 39+5=44 Cate nuci are Marian 5+25=30 Cate nuci are Alexandra 5+21=26 Verificare: 44+30+26=100

Answer 2

O /............../...+39...../
M /............./...+25../
A /............./..+21../              }100
O+39+M+25+A+21=100
3 pati+85=100
3 parti=100-85=15
1 parte=15:3=5
fiecare mananca 5 nuci;
M= 5+39=44 nuci a avut;
O=5+25=30 nuci a avut;
A=5+21=26 nuci a avut;