Question

Oxiacidul care contine 32,65% S si 65,31% O reactioneaza cu 168 g solutie de hidroxid de potasiu 10%. Ce cantitate de sare se formeaza?

Answer 1

32,65/32 = 1,02
65,31/16 = 4,08
100 - 32,65-65,31 = 2,04 % H
2,04/1 = 2,04
Imparti toate la 1,02 => oxiacidul: H2SO4
H2SO4 +  2 KOH ---> K2SO4 + 2 H2O
2*56 g KOH................174 g K2SO4
168 g KOH.................x g K2SO4        x = 261 g K2SO4