Question

oxidul de magneziu cu masa de 2g a fost tratat cu o solutie de hcl cu partea de masa 10% si densitatea =1,05gcm3 .calculati v solutiei de hcl consumat in reactie

Answer 1

MgO + 2HCl => MgCl2 + H2O

40 g MgO .... 2 x 36.5 g HCl
2 g MgO ..............a g HCl

a= $\frac{2 * (2 * 36.5)}{40}$=3.65 g HCl
c = $\frac{a}{ms} *100$ => ms=$\frac{a*100}{10}$ =36.5 g sol. HCl 10%
d=$\frac{ m_{s} }{V_s}$ => $V_{s}$= $\frac{m_s}{d}$=> Vs HCl = 36.5/1.05 = 34.76 ml sol HCl 10%