Question

Oxidul unui element X are masa moleculara 44 si contine 72,73% O. Aflati oxidul.

Answer 1

100 g oxid.............72.73 g oxigen.................27.27 g element

44 g oxid.......................................................x g element

x= 27.27 x 44/100 =12 g element .......deci 32 g O 

elementul cu masa moleculara 12 e C

deci oxidul e CO2