Question

P=1*1/2*3*1/4*...(n-1)*1/n
code blocks AJUTOOORRRR

Answer 1

#include <iostream>

using namespace std;

int main()

{

   int i, k;

   float p=0;

   cout << "introdu nr de termeni ai sumei: ";

   cin >> k;

   for (i=1; i<=k; ++i )

       p=p+(float)(2*i-1)/(2*i);

   cout << " P= " << p << endl;

}