Question

P(x)=x³+a²+3a×+1
Q(x)=x-1
R(x)=6​

Answer 1

Conform teoremei lui Bezout, R(x) = P(1)=1+a²+3a+1=a²+3a+2

Dar, R(x) = 6 ⇒ a²+3a+2 = 6⇒ a²+3a - 4=0 ⇒ a∈ {-4,  1}