Question

paranteya rotunda 1+radical din2totul la 2

Answer 1

[tex]( 1+ \sqrt{2} ) ^{2} = (1) ^{2} +2* \sqrt{2} *1+( \sqrt{2) } ^{2} = 1+ 2\sqrt{2} +2= 3+ 2\sqrt{2} [/tex]

Answer 2

(1+rad.2)la a 2=1+2^2+2=3+2^2

^-radical