Question

parte fractionara din fractie periodica gan {-2.(6)} si {3.(4)}?​

Answer 1

[-2.(6)]+{-2.(6)}= -2.(6)

-3<-2.(6)< -2

[-2.(6)]= -3

{-2.(6)}= -2.(6)- [-2,(6)]= -24/9-(-3)= -24/9+27/9=3/9=1/3

{-2.(6)}=0.(3)

[3.(4)]+{3.(4)}=3,(4)

3<3.(4)< 4

[3.(4)]=3

{3.(4)}=3,(4)-3=31/9-27/9=4/9

{3.(4)}=0.(4)