Question

Partea intreaga a numarului:
[1/radical din 10-3]=

Answer 1

Răspuns:

atunci este 6 pentru ca

$3 < \sqrt{10} < 4 \\ 0 < \sqrt{10} - 3 < 1 \\ 6 < \frac{1}{ \sqrt{10} - 3 } < 7 \\ = > \frac{1}{ \sqrt{10} - 3 } = 6$

Answer 2

$\it \Big[\dfrac{1}{\sqrt{10}-3}\Big]=6\\ \\ \\ \Big[\dfrac{1}{\sqrt{10}}-3\Big]=-3$

$\it \dfrac{^{\sqrt{10}+3)}1}{\ \ \sqrt{10}-3}=\dfrac{\sqrt{10}+3}{(\sqrt{10})^2-3^2}=\dfrac{\sqrt{10}+3}{10-9}=\sqrt{10}+3>\sqrt9+3=3+3=6$

$\it 9<10<16 \Rightarrow \sqrt9<\sqrt{10}<\sqrt{16} \Rightarrow 3<\sqrt{10}<4|_{+3} \Rightarrow 6<\sqrt{10}+3<7$