Question

Partea reala a numarului complex z = $(-1)^{2+2i}$

Answer 1

 

$\displaystyle\bf\\z=(-1)^{2+2i}\\\\z=(-1)^{2(1+i)}\\\\z=\Big((-1)^2\Big)^{(1+i)}\\\\-1~\textbf{ridicat la putere para }=1\\\\z=\Big(1\Big)^{(1+i)}\\\\1~\textbf{ridicat la orice putere }=1\\\\z=1 \in R\\\\\textbf{z nu are parte imaginara.}\\\\\textbf{Partea reala a lui } z=1$