Question

patrat perfect.

9 la puterea 27 121 la puterea 121 (2x8) la puterea 17 32 la puterea 19 : 2 la puterea 19​

Answer 1

 

Consider sa se cere sa arati ca sunt patrate perfecte.

$\displaystyle\bf\\9^{27}=\Big(3^2\Big)^{27}=3^{2\times27}=\Big(3^{27}\Big)^{2}=pp\\\\121^{121}=\Big(11^2\Big)^{121}=11^{2\times121}=\Big(11^{121}\Big)^{2}=pp\\\\(2\times8)^{17}=16^{17}=\Big(4^2\Big)^{17}=4^{2\times17}=\Big(4^{17}\Big)^{2}=pp\\\\32^{19}:2^{19}=\frac{32^{19}}{2^{19}}=\left(\frac{32}{2}\right)^{19}=\\\\=16^{19}=\Big(4^2\Big)^{19}=4^{2\times19}=\Big(4^{19}\Big)^{2}=pp$