Question

Patru copii au impreuna suma de 106 lei. Se stie ca primii doi elevi au cu 10 lei mai mult decat ultimii dou,primul are cu 4 lei mai putin decat al doilea si al patrulea are cu 8lei mai mult decat al treilea.Aflati ce suma de bani are fiecare.
DAU COROANA!
P.S Cer rezolvare algebrica si completa.

Answer 1

a+b+c+d=106
a+b=c+d+10
b=a-4
d=c+8
a+a-4=c+c+8+10
2a-4=2c+18
2(a-c)=22
a-c=11
c=a-11=>d=a-3
=>a+a-4+a-11+a-3=106
4a-18=106
4a=124
a=31
b=27
c=20
d=28

Answer 2

a+b+c+d=106

a+b=c+d+10

a=b-4

c+8=d

                                                Re-re:

106-10=96              96/2=48=a+b=c+d

a+b=48    a=48-b

a=b-4            48-b=b-4         48+4=2b=52

b=52/2=26   a=26-4=22

c+d=48        c=d-8

48-d=d-8   48+8=2d         56=2d     d=56/2=28

c=28-8=20

a+b=c+d=48

a+c=22+20=42

a+d=22+28=50

b+c=26+20=46

b+d=26+28=54