Question

Pe 4 si pe 5,va rog!
Dau coroana!

Answer 1

4)
x=√20  y×z=√45  (x×y)×z=x×y×z=√20×√45=√900=30
x×y=2√7  z×t=-7√2  x×(y×z)×t=x×y×z×t=2√7×(-7√2)=-14√14

5.
a) 2√2(5√2-6√3+√6)=10√4-12√6+2√12=20-12√6+4√3
b) -6√3(6√2+4√3-2√5)=-36√6-24√9+12√15=-36√6-72+12√15
c) 4√3(√27+√75-√243)= 4√3(3√3+5√3-9√3)= 4√3(-√3)=-12
d) √108(√288-√648+√450-√1458)= 6√3(12√2-18√2+15√2-27√2)=
= 6√3(-18√2)=-108√6