Question

Pe planul patratului ABCD latuta de 24 cm se ridică perpendiculara MD , cu MD=12radical din 2 . Aflati distanta MB, aria triunghiului MAC si perimetrul acestuia

Answer 1

DB=24√2
MB=√[(12√2)²+(24√2)²]=√(288+1152)=√1440=12√10 cm
DO=DB/2=24√2/2=12√2 cm
MO=√[(12√2)²+(12√2)²]=√(288+288)=√576=24 cm
A(MAC)=AC×MO/2=24√2×24/2=288√2 cm²
MA=MC=√[(12√2)²+24²]=√(288+576)=√864=12√6 cm
P(MAC)=24√2+12√6 +12√6 =24√2+24√6 =24√2(1+√3)