Question

pentru a obtine 2005 ce nr trebuie adaugat la egalitatea [268-89x3+(306:3+102x x):2]:2x3=834

Answer 1

[268-89*3+(306:3+102X):2]:2*3=834
[268-267+(102+102X):2]:2=834:3
[268-267+(102+102X):2]:2=278
1+(102+102X):2=278*2
1+(102+102X):2=556
1+(102+102)=556*2
1+(102+102)=1112
102+102X=1112-1
102+102X=1111
102X=1111-102
102X=1009
X=1009:102
X=9,89
X=10