Question

Pentru circuitul din figura , se cunosc : E1=40V , E2=20V , r1=r2=4ohmi , R3=1ohm , R4=6ohmi , R5=3ohmi . Calculeaza :
a)Intensitatea prin fiecare ramura
b)Tensiunea la bornele circuitului exterior

Answer 1

a) Ep/rp=E1/r1+E2/r2
1/rp=1/r1+1/r2
1/rp=1/4+1/4=>>rp=4/2=2ohm

Ep/2=40/4+20/4=15=>>Ep=30V

Re=Rp+R3
1/Rp=1/R4+1/R5=1/6+1/3=>>Rp=6/3=2ohm

Re=Rp+R3=2+1=3 ohm

I=Ep/Re+rp=30/3+2=6A

R4=2R5=>>
I5=2I4=>I4=2A, I5=4A

I=I4+I5=2+4=6A

b) Tensiunea sursei
E=U+Ir=>30=U+6•2=>U=30-12=18V