Question

Pentru substanta cu formula C₆H₄CL₂ se cere:

a) raportul atomic

b) raportul de masa

c) masa moleculara

d) formula procentuala

Answer 1

A)C:H:Cl=6:4:2=3:2:1

B)C:H:Cl=12:1:35,5

C)M=12*6+4*1+2*35,5=72+4+71=147 g/mol

D)147g C6H4Cl2....72 g C...4g H...71g Cl

100g C6H4Cl2...x g C...y g H...z g Cl

X=48,97% C

Y=2,72% H

Z=58,28% Cl