Question

Perimetrul unui patrulater este un metru.Aflati lungimile laturilor daca ele reprezinta numere pare consecutive.

Answer 1

2k+2k+2+2k+4+2k+6=100cm=1m
8k+12=100
8k=100-12
8k=88
k=88:8
k=11

2k=2x11
2k+22cm

2k+2=2x11+2
2k+2=22+2
2k+2=24cm

2k+4=2x11+4
2k+2=22+4
2k+2=26cm

2k+6=2x11+6
2k+6=22+6
2k+6=28cm

Answer 2

1m=100cm => dacă x=numar par, atunci :
x + x+2 + x+4 +x+6 = 100 (cm) ⇔ 4x+12=100 deci x=(100-12):4=22
⇒ laturile patrulaterului sunt: 22cm ;24cm ; 26cm si 28cm .