Question

Peste 200 grame de saramura de concetratie 50% se adauga 50g sare. Ce concentratie procentuala are solutia obtinuta​

Answer 1

Răspuns:

cf=60%

Explicație:

aflam prima data masa de dizolvat 1 (md1)

c/100=md/ms=>md=(c×ms)/100

md1=(50×200)/100=100g

acum, aflam masa de solutie 2 si masa de dizolvat 2

ms2=ms1+sarea adaugata=200+50=250grame

md2=md1+sarea adaugata=100+50=150grame

si apoi putem afla concentratia finala(cf)

cf/100=md2/ms2

cf/100=150/250=>c=(150×100)/250=60

cf=60%