Question

Peste 3kg saramura de concentratie 60% se adauga o alta solutie de sare in apa de concentratie 10%,obtinande se o noua solutie de concentratie 40%.calculeaza masa solutiei de concentratie 10% necesara.

Answer 1

ms 1= 3kg c1= 60% c2 =10 % c final = 40 % c1 = md1/ms1 * 100 60 = md1/ 3 * 100 md1= 1,8 kg c2 = md2/ ms2 * 100 10 md2/ ms2 * 100 ms2 = 10 md2 c final = md1 +md2/ ms1+ms2 *100 40 = ( 1,8+md2)/ ( 3+md2) * 100 4( 3+ 10md2) = 10 ( 1,8+md2) 12+ 40 md2= 18+10md2 30md2= 6 md2= 0,2 kg ms2= 10 * 0,2 ms2= 2 kg