Question

Piramida patrulatera VABCD are ca baza patratul ABCD cu centrul O.Se stie ca AB=8 si VO=3
a)Calculati lungimea apotemei VM a piramidei, unde M apartine de ab
b)Daca OP_|_VM ,unde P apartine de VM ,aratati ca OP_|_(VBC)
c)Calculati d(O,(VBC))
80 puncte repedeeeeee please!:D

Answer 1

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→ a ) OM = AB / 2 = 8 / 2 = 4

VM = √( VO² + OM² ) = √ • 3² + 4² ) = √( 9 + 16 ) = √25 = 5
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→ b ) = > OP _|_ VM ≈ > OP _|_ ( VBC ) .
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→ c ) A VOM = VO • OM / 2 = 3 • 4 / 2 = 12 / 2 = 6

A VOM = OP • 5 / 2 = 6

d( O, ( VBC ) ) = OP = 6 • 2 / 5 = 12 / 5 = 2,4 cm



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