Question

plan inclinat
alfa= 30°
m1= 2kg
m2=4kg
u=
$\frac{1}{2 \sqrt{ 3} }$
a= 5/3 m/s²
T=?

VA ROG MULT AJUTAȚI-MĂ! DAU COROANĂ! ​

Answer 1

cred ca e asa cel putin la mine in caiet asa scrie, nu sunt sigur

Vectorial:F+N+G+Ff=ma

Scalar:Ox:Fcosθ-Ff-mgsinα=ma

Oy:N+Fsinθ-mgcosα=0=>N=-Fsinθ+mgcosα

Ff=μN=μ(-Fsinθ+mgcosα)

Fcosθ-μmgcosα+μFsinθ-mgsinα=ma<=>Fcosθ+μFsinθ=ma+μmgcosα+mgsinα<=>F(cosθ+μsinθ)=m(a+μgcosα+gsinα)=>F=m(a+μgcosα+gsinα)/(cosθ+μsinθ)=2(2+0,2*10*0,866+10*0,5)/(0,7+0,7*0,2)=2(2+1,73+5)/0,84=2,38*8,73=20,7 N