Question

Please!!!

Este urgent!!!

Answer 1

9.
a)=3/9=1/3
b)=6/9=2/3
c)=7+3/9=7+1/3 (+ inseamna intregi, adica in caiet sa nu scrii + da sa scrii 7 mare si fractia 1/3).
d)=5+6/9=5+2/3
e)=4+18/99=4+2/11
f)=36/99=4/11
g)=1+3/99=1+1/33
h)=2+54/99=2+6/11

10.
a)=(13-1)/90=12/90=4/30=2/15
b)=15/90=1/6
c)=1+24/90=1+4/15
d)=2+21/90=2+7/30
e)=14+75/90=14+25/30=14+5/6
f)=1+25/900=1+1/36
g)=2430/9900=270/1100=27/110
h)=2385/9990=265/1110=53/222

Answer 2

9. a) 0,(3)= 3/9= 1/3 , b)0.(6)=$\frac{6}{9}$

c)7,(3)=$\frac{73-7}{9} = \frac{66}{9}$

d)5,(6)=$\frac{56-5}{9}= \frac{51}{9}$

e)4,(18)=$\frac{418-4}{99}= \frac{414}{9}$

f)0,(36)=$\frac{36}{99}$

g)1,(03)=$\frac{103-1}{99}= \frac{102}{99}$

h)2,(54)=$\frac{254-2}{99}= \frac{252}{99}$


10. a)0,1(3)=$\frac{13-1}{90} = \frac{12}{90}$

b)0,1(6)=$\frac{16-1}{90} = \frac{15}{90}$

c)1,2(6)=$\frac{126-12}{90}= \frac{114}{90}$

d)2,2(3)=$\frac{223-22}{90} = \frac{201}{90}$

e)14,8(3)=$\frac{1483-148}{90} = \frac{1335}{90}$

f)1,02(7)=$\frac{1027-102}{900}= \frac{925}{900}$

g)0,24(54)=$\frac{245424}{9900}= \frac{2430}{9900}$

h)0,2(387)=$\frac{2387-2}{9990}= \frac{2385}{9990}$