Question

Please!!!

Este urgent!!!

Answer 1

$\frac{2^{13}}{8^7}=\frac{2^{13}}{(2^3)^7}=\frac{2^{13}}{2^{21}}=\frac{1}{2^8} \\ \\ \frac{4^6}{16^5}=\frac{(2^2)^6}{(2^4)^5}=\frac{2^{12}}{2^{20}}=\frac{1}{2^8}$
Am ajuns la ambele la $\frac{1}{2^8}$ deci sunt echivalente