Question

Please help me !!!!!!!!!!
a) 3x-√3=√27
b) Aflati m apartinand R , stiind ca x=√2-1 este solutia ecuatiei mx+2=2√2
c) (x+√12)(x-√3)=0
d) |-√3x+√3|=√27
e) 1/√2 x-√2=0
Dau coroana please help !!!!!

Answer 1

$a).3x- \sqrt{3} = \sqrt{27} \\ 3x- \sqrt{3} =3 \sqrt{3} \\ 3x=3 \sqrt{3} + \sqrt{3} \\ 3x=4 \sqrt{3} \\ x= \frac{4 \sqrt{3} }{3} \\ b).m( \sqrt{2} -1)+2=2 \sqrt{2} \\ m \sqrt{2} -m+2=2 \sqrt{2} \\ m \sqrt{2} -m=2 \sqrt{2} -2 \\ m( \sqrt{2} -1)=2( \sqrt{2} -1) \\ m= \frac{2( \sqrt{2} -1)}{ \sqrt{2} -1} \\ m=2$
$c).(x+ \sqrt{12} )(x- \sqrt{3} )=0 \\ (x+2 \sqrt{3} )(x- \sqrt{3} )=0 \\ x+2 \sqrt{3} =0 \\ x=-2 \sqrt{3} \\ x- \sqrt{3} =0 \\ x= \sqrt{3} \\ x=-2 \sqrt{3} ;x= \sqrt{3}$
$d).|- \sqrt{3} x+ \sqrt{3} |= \sqrt{27} \\ |- \sqrt{3} x+ \sqrt{3} |=3 \sqrt{3} \\ - \sqrt{3} x+ \sqrt{3} =-3 \sqrt{3} \\ - \sqrt{3} x=-3 \sqrt{3} - \sqrt{3} \\ - \sqrt{3} x=-4 \sqrt{3} \\ x= \frac{4 \sqrt{3} }{ \sqrt{3} } \\ x=4 \\ - \sqrt{3} x+ \sqrt{3} =3 \sqrt{3} \\ - \sqrt{3} x=3 \sqrt{3} - \sqrt{3} \\ - \sqrt{3} x=2 \sqrt{3} \\ x=- \frac{2 \sqrt{3} }{ \sqrt{3} } \\ x=-2 \\ x=-2;x=4$
$e). \frac{1}{ \sqrt{2} } x- \sqrt{2} =0 \\ x-2=0 \\ x=0+2 \\ x=2$