Question

pls ajutor la tema, primul răspuns primește coroana, cele încercuite, rezultatul sa fie ireductibil ​

Answer 1

Răspuns:

6. a) $\frac{5}{7} * \frac{42}{15}$ = $\frac{6}{3}$ = 2       b) $\frac{17}{150} * \frac{300}{34}$= $\frac{2}{2}$ = 1  se simplifica 150 cu 300 si 17 cu 34

c) 11 * $\frac{6}{20*6+1}$= $\frac{11*6}{121}$ = $\frac{6}{11}$

7.  $\frac{3}{4} : \frac{2*3+1}{3}$ = $\frac{3}{4} * \frac{3}{7}$ = $\frac{9}{28}$             $\frac{7}{3} : \frac{3}{4}$ = $\frac{7}{3} *\frac{4}{3}$ = $\frac{28}{9}$

$\frac{3*5+1}{5} : \frac{1*4+1}{4}$ = $\frac{16}{5} * \frac{4}{5}$ = $\frac{64}{25}$         $\frac{5}{4} : \frac{16}{5}$ =$\frac{5}{4} * \frac{5}{16}$ = $\frac{25}{64}$

9.  a) $\frac{19}{130} * \frac{260}{38} =$ $\frac{2}{2} =1$      b) $\frac{17}{1} : \frac{6*31+1}{6}$ = $\frac{17}{1} * \frac{6}{187}$ = $\frac{6}{11}$

c) $\frac{14}{1} : \frac{3*2+1}{2}$ =  $\frac{14}{1} * \frac{2}{7}$ = 4      d) $\frac{3*6+5}{6} : \frac{12*1+11}{12}$= $\frac{23}{6} * \frac{12}{23}$ =2

e) $\frac{3*5+4}{5} : \frac{1*17+2}{17} =$$\frac{19}{5} * \frac{17}{19}$= $\frac{17}{5}$    

g) $\frac{4*31+1 }{4} :\frac{20*6+5}{6}$ =  $\frac{125}{4} * \frac{6}{125}$= $\frac{6}{4} =\frac{3}{2}$

h) $\frac{3*20+2}{3} : \frac{4*15+2}{4}$ = $\frac{62}{3} * \frac{4}{62}$ = $\frac{4}{3}$