Question

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Answer 1

a) m(ADB) = m(arcAB)/2 = 120/2 = 60
    m(BDC) = m(arcBC)/2 = 50/2 = 25 
    m(DAC) = m(arcDC)/2 = 140/2 = 70
b) m(<A) = m(arc BC + DC)/2 = (50 + 140)/2 = 190/2 = 95
    m(arcAD) = m(arcBC) = 50
    m(<B) = m(<A) = 95
    m(<C) = m(arc AD + AB) = (50 + 120)/2 = 170/2 = 85
    m(<D) = m(<C) = 85