Question

Pls dau coroana!!!!!!!!!!!!​

Answer 1

1

a.

stim ca [H3O+]*[HO-] = 10⁻¹⁴

=> [HO-] = 10⁻¹⁴/[H3O+]

= 10⁻¹⁴/2*10⁻⁸ = 5*10⁻⁷ mol/L

caracter bazic, deoarece [H3O+] < [HO-]

b.

stim ca [H3O+]*[HO-] = 10⁻¹⁴

=> [HO-] = 10⁻¹⁴/[H3O+]

= 10⁻¹⁴/10⁻¹³ = 10⁻¹ mol/L

caracter bazic, deoarece [H3O+] < [HO-]

c.

stim ca [H3O+]*[HO-] = 10⁻¹⁴

=> [HO-] = 10⁻¹⁴/[H3O+]

= 10⁻¹⁴/4*10⁻⁴ = 2,5*10⁻¹¹ mol/L

caracter acid, deoarece [H3O+] > [HO-]

2.

a.

stim ca [H3O+]*[HO-] = 10⁻¹⁴

=> [H3O+] = 10⁻¹⁴/[HO-]

= 10⁻¹⁴/4*10⁻³ = 2,5*10⁻¹² mol/L

caracter bazic, deoarece [H3O+] < [HO-]

b.

stim ca [H3O+]*[HO-] = 10⁻¹⁴

=> [H3O+] = 10⁻¹⁴/[HO-]

= 10⁻¹⁴/10⁻⁹ = 10⁻⁵ mol/L

caracter acid, deoarece [H3O+] > [HO-]

c.

stim ca [H3O+]*[HO-] = 10⁻¹⁴

=> [H3O+] = 10⁻¹⁴/[HO-]

= 10⁻¹⁴/10⁻³ = 10⁻¹¹ mol/L

caracter bazic, deoarece [H3O+] < [HO-]