Question

Pls dau coroana mssssssss​

Answer 1

${3}^{n} + {3}^{n + 1} + {3}^{n + 2} + {3}^{n + 3} + {3}^{n + 4} = {3}^{n} + {3}^{n} \times 3 + {3}^{n} \times {3}^{2} + {3}^{n} \times {3}^{3} + {3}^{n} \times {3}^{4} = {3}^{n}(1 + 3 + {3}^{2} + {3}^{3} + {3}^{4}) = {3}^{n}(1 + 3 + 9 + 27 + 81) = {3}^{n} \times 121 = {3}^{n} \times {11}^{2}$

Iar rezultatul final este divizibile cu 11, ceea ce trebuia demonstrat.

Sper ca te-am ajutat!