Question

plss repede dau coroana :g și i" metoda mersului invers plss
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Answer 1

g)6+[15-(8:ax7+7)]x5=8:(1x4)+3x3

6+[15-(8:ax7+7)]x5=8:4+9

6+[15-(8:ax7+7)]x5=2+9

6+[15-(8:ax7+7)]x5=11

[15-(8:ax7+7)]x5=11-6 [15-(8:ax7+7)]x5=5

[15-(8:ax7+7)]=5:5 15-(8:ax7+7)=1

(8:ax7+7)=15-1

8:ax7+7=14 8:ax7=14-7

8:ax7=7

8:a=7:7

8:a=1

a=8

i) [(6*137-364:i):7+139]:3=834-751 [(6*137-364:1):7+139]:3=83

(6*137-364:1):7+139=83*3

(6*137-364:1):7+139=249 (6*137-364:i):7=249-139

(6*137-364:1):7=110 6*137-364:i=110*7

6*137-364:i=770

822-364:1-770

364:1-822-770

364:1-52

i=364:52

i=7