Question

Plsss exxx 2.... Dauuuu coroanaaaaaa!!!!!!

Answer 1

 

$\displaystyle\\\text{Ex. 2}\\\\a)~\text{Comparam:}\\\\5^8~cu~2^{15}+2\cdot4^7\\5^8~cu~2^{15}+2\cdot\Big(2^2\Big)^7\\5^8~cu~2^{15}+2\cdot2^{14}\\5^8~cu~2^{15}+2^{15}\\5^8~cu~2\cdot2^{15}\\5^8~cu~2^{16}\\5^{2\times4}~cu~2^{4\times4}\\\Big(5^2\Big)^4~cu~\Big(2^4\Big)^4\\25^4>16^4\\\implies~~\boxed{5^8~>~2^{15}+2\cdot4^7}\\\\\\b)~\text{Comparam:}\\\\5^{14}~cu~3^{21}\\5^{2\times7}~cu~3^{3\times7}\\\Big(5^2\Big)^7~cu~\Big(3^3\Big)^7\\25^7<27^7\\\implies~~\boxed{5^{14}<3^{21}}$