Question

Plssss urgent !!!!!! Aflati nr x,y, z, stiind ca ele sunt direct proportionale cu :
0,(3) ; 0,(6) ; 0,(7) si 5x+2y-3z=18

Answer 1

x/0,(3)=y/0,(6)=z/0,(7)=k => 
=> x=k*0,(3)
y=k*0,(6)
z=k*0,(7)

 5x+2y-3z=18 <=> 5*k*0,(3)+2*0,(6)-3*0,(7)=18 <=> (15/9)*k+(12/9)*k-(21/9)*k=18 <=> (6/9)*k=18 => k=(18*9)/6 => k=27

x=27*(3/9)=9
y=18
z=21