Question

Plsssss va rog enorm

Answer 1

M,Ag= 108g/mol
M,AgNO3=170g/mol
M,Cu= 63g/mol

nAg=m/M= 54g/108g/mol= 0,5mol


Cu     +  2AgNO3-------> Cu(NO3)2    +  2Ag
1mol.........2mol......................................2mol
x..............y.............................................0,5mol
y-=0,5molAgNO3
m= nxM= 0,5molX170g/mol= 85g  AgNO3---->este md in relatia
c= mdx100/ms--> 25= 85x100/ms..............................calculeaza ms !!!!!


x=0,25molCu
m=.0,25molx63g/mol=15,75g Cu pur
p=80%
p= m,px100/m,impur----->
80= 15,75x100/m,impur----------------calculeaza m,impur !!!!!!!!!