Question

plz ajutațima va rog ​

Answer 1

Răspuns:

1.a. m AOB = m COA -m BOC = 180-45=135°

b.M AOB = m AOD - m DOC -mCOB =180-90-58=32°

c.m AOB = m DOC - m DOB - m AOC = 180-31-48=101°

2.a. 40°54'10"

b.43°57'43"

c.144°27'36"

Answer 2

Răspuns:

Explicație pas cu pas:

1. a) ∠AOB=180°-45°=135°

2 b) ∠AOB=90°-58°=32°

c) ∡DOB+∡AOB+∡AOC=180°

31°+∡AOB+48°=180° ∡AOB=180°-(31+48°)=180°-79°=101°

2

13°14'23"+27°39'47"=40°53'70"=40°54'10"

56°12'39"-12°24'56"= 55°71'99"-12°24'56"=43°47'43"

72°13'48"×2=144°26'96"=144°27'36"